–ÚŽŸƒ‚ƒNƒW‚Ö�@�@�y“Æ—§Šî‘b_Ccƒ^ƒCƒv�z �Ý”õ‘Ï�k_“Æ—§ƒhƒNƒŠƒcŠî‘bƒLƒ\_Cc
�œŠî‘bƒLƒ\‚Ì•‚ƒE‚«�ãƒA‚ª‚è‚ÌŒŸ“¢ƒPƒ“ƒgƒE
(1-Kv)[(Lg+(Lf-L)/2)*W+Lf*Wf/2] > Kh[(hf+hg)*W+hf*Wf/2]
(1-0.5)[(30+(130-60)/2)*1.9+130*15E+00/2]=67E+01>1[(50+90)*1.9+50*15/2]=64E+01 FALSE
�œ”»’è OK 1
‚±‚±‚Å�A L=�Ý”õ‹@Ší‚Ì•�=60[cm] 60
Lg=�Ý”õ‹@Ší‚Ì�d�SˆÊ’u=30[cm]
“Æ—§Šî‘b_Cc_1.jpg
30
hg=�Ý”õ‹@Ší�d�S�‚‚³=90[cm] 90
Lf=Šî‘b’·‚³=130[cm] 130
hf=Šî‘b�‚‚³=50[cm] 50
Bf=Šî‘b•�=50cm] 50
Kh=�ÝŒv—p�…•½�k“x=1 1
Kv=�ÝŒv—p‰”’¼�k“x=0.5
W=�Ý”õ‹@Ší�d—Ê=1.9[kN] 1.9
Wf0=Šî‘b�d—Ê=Wf+Wr
   =15+3.59=18.59[kN]
Wf=Šî‘b�d—Ê
    =50*130*50*0.000023=15[kN]
Wr=ƒ‰ƒtƒRƒ“ƒNƒŠ�[ƒg�d—Ê=hr*(Br^2-Bf^2)*Z*ƒÁ
  =20*(80^2-50^2)*2*0.000023=3.59[kN]
hr=ƒ‰ƒtƒRƒ“ƒNƒŠ�[ƒg�‚‚³=20[cm] 20
Lr=ƒ‰ƒtƒRƒ“ƒNƒŠ�[ƒg’·‚³=[cm]
Br=ƒ‰ƒtƒRƒ“ƒNƒŠ�[ƒg•�=80[cm]
La=ƒ_ƒ{‹Ø–„�ž‚Ý’·=15[cm] 15
ƒÁ=ƒRƒ“ƒNƒŠ�[ƒg”ä�d—Ê=23E-06[kN/cm3] 23
z=Šî‘bŒÂ�”=2 2