–ÚŽŸƒ‚ƒNƒW‚Ö@@y“Æ—§Šî‘b_Ccƒ^ƒCƒvz Ý”õ‘Ïk_“Æ—§ƒhƒNƒŠƒcŠî‘bƒLƒ\_Cc
œŠî‘bƒLƒ\‚Ì•‚ƒE‚«ãƒA‚ª‚è‚ÌŒŸ“¢ƒPƒ“ƒgƒE
(1-Kv)[(Lg+(Lf-L)/2)*W+Lf*Wf/2] > Kh[(hf+hg)*W+hf*Wf/2]
(1-0.5)[(30+(130-60)/2)*1.9+130*15E+00/2]=67E+01>1[(50+90)*1.9+50*15/2]=64E+01 FALSE
œ”»’è OK 1
‚±‚±‚ÅA L=Ý”õ‹@Ší‚Ì•=60[cm] 60
Lg=Ý”õ‹@Ší‚ÌdSˆÊ’u=30[cm]
“Æ—§Šî‘b_Cc_1.jpg
30
hg=Ý”õ‹@ŠídS‚‚³=90[cm] 90
Lf=Šî‘b’·‚³=130[cm] 130
hf=Šî‘b‚‚³=50[cm] 50
Bf=Šî‘b•=50cm] 50
Kh=ÝŒv—p…•½k“x=1 1
Kv=ÝŒv—p‰”’¼k“x=0.5
W=Ý”õ‹@Šíd—Ê=1.9[kN] 1.9
Wf0=Šî‘bd—Ê=Wf+Wr
   =15+3.59=18.59[kN]
Wf=Šî‘bd—Ê
    =50*130*50*0.000023=15[kN]
Wr=ƒ‰ƒtƒRƒ“ƒNƒŠ[ƒgd—Ê=hr*(Br^2-Bf^2)*Z*ƒÁ
  =20*(80^2-50^2)*2*0.000023=3.59[kN]
hr=ƒ‰ƒtƒRƒ“ƒNƒŠ[ƒg‚‚³=20[cm] 20
Lr=ƒ‰ƒtƒRƒ“ƒNƒŠ[ƒg’·‚³=[cm]
Br=ƒ‰ƒtƒRƒ“ƒNƒŠ[ƒg•=80[cm]
La=ƒ_ƒ{‹Ø–„ž‚Ý’·=15[cm] 15
ƒÁ=ƒRƒ“ƒNƒŠ[ƒg”äd—Ê=23E-06[kN/cm3] 23
z=Šî‘bŒÂ”=2 2